Hi all,

I have converted an array of bytes into a string. Worked like a charm with the oscat function btw.
Now i have to put it into hex-values. Any way to create a string with hex values?

Thanks

Originally created by: scott_cunningham

You can make your own solution by using two offsets. Look at each byte. If it is >=10 then add 55 to it (A is ascii 65). For smaller number, add ascii offset for 0 - sorry don't remember if it is 40 or 42). Examine bytes from highest to lowest and con at your chars.

There is probably a prebuilt function somewhere, but it may take you longer searching for it than building it.

scott_cunningham hat geschrieben:
You can make your own solution by using two offsets. Look at each byte. If it is >=10 then add 55 to it (A is ascii 65). For smaller number, add ascii offset for 0 - sorry don't remember if it is 40 or 42). Examine bytes from highest to lowest and con at your chars.
There is probably a prebuilt function somewhere, but it may take you longer searching for it than building it.

OK that's great but still facing a major problem for me.
Let's say i got value 58 in one byte. Then i want it displayed as 3A. (Hex is 4 bits). And i don't see any solution in it then

Originally created by: scott_cunningham

58 = 0011 1010 in binary. Hex uses four bits (nibble). You have to look at the upper four bits (3), then the lower four bits (A).

A WORD uses two bytes (four nibbles) and can have a number from 0000 to FFFF hex.
A BYTE uses one byte (two nibbles) and can have a number from 00 to FF hex.

Here is a crude function to convert a BYTE to a two char string. It is up to you to expand it for longer variable types...

FUNCTION BYTE_TO_HEX_STRING : STRING
VAR_INPUT
Input : BYTE;
END_VAR
VAR
Temp : BYTE;
Chr : BYTE;
Ans : STRING;
END_VAR

Temp := SHR(Input, 4);
IF Temp > 9 THEN
Chr := Temp + 55;
ELSE
Chr := Temp + 48;
END_IF
Ans[0] := Chr;

Temp := SHR(SHL(Input,4),4); //wipes upper nibble (could also mask...)
IF Temp > 9 THEN
Chr := Temp + 55;
ELSE
Chr := Temp + 48;
END_IF
Ans[1] := Chr;
Ans[2] := 0; //null char

BYTE_TO_HEX_STRING := Ans;

scott_cunningham hat geschrieben:
58 = 0011 1010 in binary. Hex uses four bits (nibble). You have to look at the upper four bits (3), then the lower four bits (A).
A WORD uses two bytes (four nibbles) and can have a number from 0000 to FFFF hex.
A BYTE uses one byte (two nibbles) and can have a number from 00 to FF hex.
Here is a crude function to convert a BYTE to a two char string. It is up to you to expand it for longer variable types...
FUNCTION BYTE_TO_HEX_STRING : STRING
VAR_INPUT
Input : BYTE;
END_VAR
VAR
Temp : BYTE;
Chr : BYTE;
Ans : STRING;
END_VAR
Temp := SHR(Input, 4);
IF Temp > 9 THEN
Chr := Temp + 55;
ELSE
Chr := Temp + 48;
END_IF
Ans[0] := Chr;
Temp := SHR(SHL(Input,4),4); //wipes upper nibble (could also mask...)
IF Temp > 9 THEN
Chr := Temp + 55;
ELSE
Chr := Temp + 48;
END_IF
Ans[1] := Chr;
Ans[2] := 0; //null char
BYTE_TO_HEX_STRING := Ans;

Thanks
I managed to get it to work for longer variable types. Worked like a charm

Hello NBCC, I work on the same problem as you but I have to work with WORDs and not BYTEs, could you please explain me how did you managed to get it to work for longer variable types ?

I know this is an old post but I still hope that someone will answer...

in fact (this question is more for scott_cunningham) , I don't understand why and what is really done here :
"
Temp := SHR(Input, 4);
IF Temp > 9 THEN
Chr := Temp + 55;
ELSE
Chr := Temp + 48;
END_IF
"

Thanks