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Fehler: " kein gültiges Zuweisungsziel. "

Engineering 🇬🇧
mariusfg
2017-01-19
2017-01-19

  • mariusfg - 2017-01-19

    Hallo,

    ich bin neu mit Codesys unterwegs.
    Habe einen Funktionsblock generiert.

    Es erscheinen die Fehlermeldungen "TRUE AND boEVU30" ist kein gültiges Zuweisungsziel.

    Ich gehe von einem Syntaxfehler aus. 

    FUNCTION_BLOCK FB_PowerSteps
VAR_INPUT
   iEVU_Pro: INT; //Prozentzahl der Leistungsforderung EVU
END_VAR
VAR_OUTPUT
   boEVU60: BOOL;
   boEVU30: BOOL;
   boEVU00: BOOL;
END_VAR
VAR
   iMerkerEVU_Pro: INT := 100;
END_VAR

    IF (iEVU_Pro = 60 AND iMerkerEVU_Pro = 60)
        THEN boEVU60 := TRUE AND boEVU30 := FALSE AND boEVU00 := FALSE; 
   ELSIF (iEVU_Pro = 30 AND iMerkerEVU_Pro = 30)
       THEN boEVU60 := FALSE AND boEVU30 := TRUE AND boEVU00 := FALSE;
   ELSIF (iEVU_Pro = 0 AND iMerkerEVU_Pro = 0) 
      THEN boEVU60 := FALSE AND boEVU30 := FALSE AND boEVU00 := TRUE;
   ELSE boEVU60 := FALSE AND boEVU30 := FALSE AND boEVU00 := FALSE;   // alle Werte deaktivieren >> 100 % Einspeisung in allen anderen Fällen
END_IF;

    Danke für eure Hilfe. (Sorry, Thema war erst im falschen Bereich)

     

  • Anonymous - 2017-01-19

    Originally created by: Massimo.Milluzzo

    You can use the keyword AND only during the evaluation of an expression.
    You have to split the assignments and put a semicolon at the end of each one, like this

    IF (iEVU_Pro = 60 AND iMerkerEVU_Pro = 60) THEN 
   boEVU60 := TRUE ;
   boEVU30 := FALSE;
   boEVU00 := FALSE; 
ELSIF (iEVU_Pro = 30 AND iMerkerEVU_Pro = 30)  THEN 
   boEVU60 := FALSE;
   boEVU30 := TRUE;
   boEVU00 := FALSE;
ELSIF (iEVU_Pro = 0 AND iMerkerEVU_Pro = 0) THEN 
   boEVU60 := FALSE;
   boEVU30 := FALSE;
   boEVU00 := TRUE;
ELSE 
   boEVU60 := FALSE;
   boEVU30 := FALSE;
   boEVU00 := FALSE;   // alle Werte deaktivieren >> 100 % Einspeisung in allen anderen Fällen
END_IF;
     

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